Đề thi Giữa kì 1 Toán 10 năm 2024-2025 trường THPT chuyên Trần Phú (Hải Phòng)

$\{6;9\}$

$\{1;2;3;5\}$

$\{1;3\}$

$\{1;3;6;9\}$

$b^2 = a^2 + c^2 + ac$

$b^2 = a^2 + c^2 - 3ac$

$b^2 = a^2 + c^2 - ac$

$b^2 = a^2 + c^2 + 3ac$

$\overline{P} : "\exists x \in \mathbb{R}, x^2 - x + 3 < 0"$

$\overline{P} : "\exists x \in \mathbb{R}, x^2 - x + 3 \leq 0"$

$\overline{P} : "\forall x \in \mathbb{R}, x^2 - x + 3 < 0"$

$\overline{P} : "\forall x \in \mathbb{R}, x^2 - x + 3 \leq 0"$

$20\sqrt{3}$

$10\sqrt{3}$

20.

10.

$x - 2y^2 \leq 4$.

$-x + 3y - 1 < 0$.

$y + 2 \geq 0$.

$2x - 3 \geq 0$.

$30^0.$

$90^0.$

$45^0.$

$60^0.$

$(x; y) = (-2; 2)$.

$(x; y) = (4; -1)$.

$(x; y) = (-1; 1)$.

$(x; y) = (-1; 2)$.

$-\frac{12}{13}$

$\frac{12}{13}$

$\frac{8}{13}$

$-\frac{8}{13}$

$Q \Rightarrow P$

$\overline{Q} \Rightarrow P$

$\overline{P} \Rightarrow Q$

$Q \Rightarrow \overline{P}$