Đề thi Giữa kì 1 Toán 11 năm 2025-2026 THPT Việt Đức (Hà Nội)

$\dfrac{40}{3} \text{ cm}$.

$\dfrac{20}{3} \text{ cm}$.

$\dfrac{40\pi}{3} \text{ cm}$.

$\dfrac{20\pi}{3} \text{ cm}$.

$\sin (a - b) = \sin a \cos b + \cos a \sin b$.

$\sin (a + b) = \sin a \cos b - \cos a \sin b$.

$\cos (a + b) = \cos a \cos b + \sin a \sin b$.

$\cos (a - b) = \cos a \cos b + \sin a \sin b$.

$\dfrac{3\pi}{5}$

$\dfrac{2\pi}{5}$

$\dfrac{5\pi}{3}$

$\dfrac{5\pi}{2}$

$SN$

$SM$

$MN$

$ME$

$\dfrac{\pi}{2}$

$k2\pi,k\in \mathbb{Z}$

$\pi$

$2\pi$

$-\dfrac{1}{3} \le m \le \dfrac{1}{3}$

$0 \le m \le 1$

$-3 \le m \le 3$

$-1 \le m \le 1$

$\mathbb{R} \setminus \left\{ \dfrac{\pi}{4} + k\dfrac{\pi}{2}\mid k \in \mathbb{Z} \right\}$

$\mathbb{R} \setminus \left\{ \dfrac{\pi}{4} + k\pi \mid k \in \mathbb{Z} \right\}$

$\mathbb{R} \setminus \left\{ \dfrac{\pi}{2} + k\pi \mid k \in \mathbb{Z} \right\}$

$\mathbb{R}$

$-\dfrac{7}{9}$

$\dfrac{7}{9}$

$\dfrac{2}{3}$

$\dfrac{8}{9}$

$x = \dfrac{\pi}{2} + k2\pi, k \in \mathbb{Z}$

$x = \pi + k2\pi, k \in \mathbb{Z}$

$x = k2\pi, k \in \mathbb{Z}$

$x = \pi + k\pi, k \in \mathbb{Z}$