Đề thi Giữa kì 2 Toán 10 năm 2025-2026 trường THPT Phan Bội Châu (Khánh Hòa)

A. $\vec{u}.\vec{v} = 11$.

B. $\vec{u}.\vec{v} = -3$.

C. $\vec{u}.\vec{v} = 12$.

D. $\vec{u}.\vec{v} = -4$.

A. $f(x) = ax^2 + bx + c$.

B. $f(x) = x^2 + 3x - 1$.

C. $f(x) = 3x + 2$.

D. $f(x) = x^2 - 2\sqrt{x}$.

A. $f(x) < 0, \forall x \in \mathbb{R}$.

B. $f(x) \leq 0, \forall x \in \mathbb{R}$.

C. $f(x) > 0, \forall x \in \mathbb{R}$.

D. $f(x) \geq 0, \forall x \in \mathbb{R}$.

A. $AB = \sqrt{(x_B + x_A)^2 + (y_B + y_A)^2}$.

B. $AB = \sqrt{(y_A - x_A)^2 + (y_B - x_B)^2}$.

C. $AB = \sqrt{(x_B - x_A)^2 - (y_B - y_A)^2}$.

D. $AB = \sqrt{(x_B - x_A)^2 + (y_B - y_A)^2}$.

A. $ax^2 + bx + c \leq 0$.

B. $x^2 - 2x - 1 > 0$.

C. $2x^2 - 1 > 0$.

D. $-3x^2 + bx + c \leq 0$.

-3.

3.

$3\sqrt{5}$.

$5\sqrt{3}$.

$\overrightarrow{u_1}=(1;3)$.

$\overrightarrow{u_2}=(2;1)$.

$\overrightarrow{u_3}=(1;-3)$.

$\overrightarrow{u_4}=(2;-1)$.

$d_1 : 2x-y-8=0$.

$d_2 : 2x+y-4=0$.

$d_3 : 2x-y-4=0$.

$d_4 : -2x-y-4=0$.

$I(1;-4), R=5$.

$I(-1;4), R=5$.

$I(-1;4), R=25$.

$I(1;-4), R=25$.