Đề thi Học kì 1 Toán 10 năm 2023-2024 trường chuyên Lê Khiết (Quảng Ngãi)

$130^\text{o}$

$140^\text{o}$

$50^\text{o}$

$40^\text{o}$

5,5

7,5

6

6,5

(-3; 2)

(2; -3)

(2; 3)

(3; 2)

$b^2 = a^2 + c^2$

$a^2 = b^2 + c^2 + 2bc.\cos A$

$-\dfrac{a}{\cos A} = -\dfrac{b}{\cos B} = -\dfrac{c}{\cos C}$

$c^2 = a^2 + b^2 - 2ab.\cos C$

$\Delta_a = \left|a\right|$

$\Delta_a = a - \bar{a}$

$\Delta_a = \bar{a} - a$

$\Delta_a = \left|\bar{a} - a\right|$

$\left|\overrightarrow{AC}\right| = \overrightarrow{BC}$

$\overrightarrow{AB}$ cùng hướng với $\overrightarrow{BC}$

$\left|\overrightarrow{AB}\right| = a$

$\overrightarrow{AC} = a$

$\overrightarrow{BD}$

$\overrightarrow{AC}$

$\overrightarrow{DB}$

$\overrightarrow{CA}$

$\cos(180^\text{o} - \alpha) = - \sin \alpha$

$\cos(180^\text{o} - \alpha) = \sin \alpha$

$\cos(180^\text{o} - \alpha) = \cos \alpha$

$\cos(180^\text{o} - \alpha) = - \cos \alpha$

$\overrightarrow{AI} + \overrightarrow{AB} = \vec{0}$

$\overrightarrow{CI} + \overrightarrow{AI} = \vec{0}$

$\overrightarrow{AI} + \overrightarrow{BI} = \vec{0}$

$\overrightarrow{BI} + \overrightarrow{CI} = \vec{0}$

A. (1;3).

B. (-1;1).

C. (-1;0).

D. (0;1).

A. $a<2$.

B. 123 là số nguyên tố phải không?

C. $5+x=3x^2$.

D. Quảng Ngãi là tỉnh thuộc miền Trung Việt Nam.

A. $\overrightarrow{GA}+\overrightarrow{GB}-\overrightarrow{GC}=\vec{0}$.

B. $\overrightarrow{GA}+\overrightarrow{GB}=2\overrightarrow{GC}$.

C. $\overrightarrow{GA}+\overrightarrow{GB}+\overrightarrow{GC}=\vec{0}$.

D. $\overrightarrow{GA}+\overrightarrow{GB}=\overrightarrow{GC}$.

A. $\sin \alpha <0$.

B. $\tan \alpha <0$.

C. $\cot \alpha >0$.

D. $\cos \alpha >0$.

A. $\overrightarrow{AB}=(-2;-1)$.

B. $\overrightarrow{AB}=(4;9)$.

C. $\overrightarrow{AB}=(2;1)$.

D. $\overrightarrow{AB}=(1;2)$.

A. 6 .

B. 12 .

C. 13 .

D. 2 .

A. $G(4;2)$.

B. $G(2;4)$.

C. $G(8;4)$.

D. $G\left(4;\dfrac{10}{3}\right)$.

A. $2x+3y<5$.

B. $\dfrac{1}{2}x^2+3y+5<0$.

C. $2x+3y^2 \geq 5$.

D. $x^2+y^2 \leq 0$.

A. $\vec{a}.\vec{b}=|\vec{a}|.|\vec{b}|.\sin(\widehat{\vec{a},\vec{b}})$.

B. $\vec{a}.\vec{b}=|\vec{a}|.|\vec{b}|.\cos(\widehat{\vec{a},\vec{b}})$.

C. $\vec{a}.\vec{b}=\left|\vec{a}\vec{b}\right|.\cos(\widehat{\vec{a},\vec{b}})$.

D. $\vec{a}.\vec{b}=|\vec{a}|.|\vec{b}|$.

A. 0 .

B. 1 .

C. 2 .

D. 3 .

A. $a=\pm 1$.

B. $a \neq \pm 1$.

C. $a=0$.

D. $a>1$.

$(-\infty;2) \cup [5; + \infty)$

$(-\infty;2] \cup (5; + \infty)$

$(-\infty;2)$

$[5; + \infty)$

$\dfrac{2\sqrt{3}a}{3}$

$\sqrt{3}a$

$\dfrac{\sqrt{3}a}{3}$

$2\sqrt{3}a$

$\overrightarrow{AG} = \dfrac{2\vec{a} + \vec{b}}{3}$

$\overrightarrow{AG} = \dfrac{\vec{a} + \vec{b}}{3}$

$\overrightarrow{AG} = \dfrac{\vec{a} - \vec{b}}{3}$

$\overrightarrow{AG} = \dfrac{\vec{a} + 2\vec{b}}{3}$

$\dfrac{a\sqrt{3}}{2}$

$a\sqrt{3}$

$\dfrac{a}{2}$

$a$

$\cos\alpha = \dfrac{\sqrt{6}}{3}$

$\cos\alpha = \dfrac{\sqrt{6}}{4}$

$\cos\alpha = - \dfrac{\sqrt{6}}{4}$

$\cos\alpha = - \dfrac{\sqrt{6}}{3}$

$\overrightarrow{AH} . \overrightarrow{BC} = -a^2 \sqrt{3}$

$\overrightarrow{AH} . \overrightarrow{BC} = 0$

$\overrightarrow{AH} . \overrightarrow{BC} = 2a^2 \sqrt{3}$

$\overrightarrow{AH} . \overrightarrow{BC} = a^2 \sqrt{3}$

$M(0;-17)$

$M(17;0)$

$M(-17;0)$

$M(0;17)$

$|\overrightarrow{F_1} + \overrightarrow{F_3}| = |\overrightarrow{F_2}|$

$\overrightarrow{F_1} + \overrightarrow{F_2} + \overrightarrow{F_3} = \vec{0}$

$\overrightarrow{F_1} + \overrightarrow{F_2} = \overrightarrow{F_3}$

$\overrightarrow{F_3} + \overrightarrow{F_2} = - \overrightarrow{F_1}$

A. $C\left(0;\dfrac{3}{2}\right)$

B. $C(6;0)$

C. $C(0;-6)$

D. $C\left(\dfrac{3}{2};0\right)$

A. $I\left(-\dfrac{3}{2};2\right)$

B. $I(0;14)$

C. $I\left(\dfrac{1}{2};4\right)$

D. $I(-4;10)$

A. $60^\circ$.

B. $75^\circ$ .

C. $45^\circ$

D. $30^\circ$ .

A. 5.

B. 8.

C. 6.

D. 7.