Đề thi Học kì 1 Toán 10 năm 2024-2025 Sở Bắc Giang

$\{1;2;3;5;7;9;11\}$

$\{1;9\}$

$\{2;11\}$

$\{3;5;7\}$

$8\sqrt{6}$

$16\sqrt{2}$

16

32

$\exists x \in \mathbb{R}, x^2 < 0$

$\exists x \in \mathbb{R}, x^2 \ge 0$

$\forall x \in \mathbb{R}, x^2 < 0$

$\exists x \in \mathbb{R}, x^2 \le 0$

$\cos \alpha < 0$

$\sin \alpha < 0$

$\cot \alpha > 0$

$\tan \alpha > 0$

$\sqrt{57}$

$\sqrt{141}$

13

169

$\overrightarrow{CB} + \overrightarrow{CD} = \overrightarrow{AC}$

$\overrightarrow{BA} + \overrightarrow{CB} = \overrightarrow{AC}$

$\overrightarrow{AB} + \overrightarrow{AD} = \overrightarrow{AC}$

$\overrightarrow{AD} + \overrightarrow{CD} = \overrightarrow{AC}$

$3^{2}x - 5y < 6$

$x + \dfrac{1}{y} \le 2$

$x^2 + y > 5$

$\sqrt{x} + y \ge 3$

$\mathbb{R} \backslash \{ -1; 2\}$

$\mathbb{R}$

$\mathbb{R} \backslash \{ -1\}$

$\mathbb{R} \backslash \{ 2\}$

$P(0;2)$

$N(2;0)$

$M(1;0)$

$Q(1;3)$

3

6

9

8

$\overrightarrow{MG} = - \dfrac{1}{3} \overrightarrow{AM}$

$\overrightarrow{AG} = 2 \overrightarrow{MG}$

$\overrightarrow{AG} = \dfrac{2}{3} \overrightarrow{AM}$

$\overrightarrow{AM} = 3 \overrightarrow{GM}$

$x - y + 7 < 0$

$4x > 3y$

$2x - 3y - 1 > 0$

$x - y < 0$