Đề thi Học kì 1 Toán 10 năm 2025-2026 trường THPT Việt Đức (Hà Nội)

120°

30°

60°

150°

8143000.

8141400.

8142400.

8141000.

$\exists x \in \mathbb{R}: x^2 = x$.

$\exists x \in \mathbb{R}: x > x^2$.

$\forall x \in \mathbb{R}: x = x^2$.

$\forall x \in \mathbb{R}: x > x^2$

$\cos \left(\vec{u};\vec{v}\right) = - \dfrac{\sqrt{10}}{10}$.

$\cos \left(\vec{u};\vec{v}\right) = - \dfrac{3\sqrt{10}}{10}$.

$\cos \left(\vec{u};\vec{v}\right) = \dfrac{3\sqrt{10}}{10}$.

$\cos \left(\vec{u};\vec{v}\right) = \dfrac{\sqrt{10}}{10}$

$\overrightarrow{AB} + \overrightarrow{CB} = \overrightarrow{AC}$.

$\overrightarrow{AB} + \overrightarrow{BC} = \overrightarrow{AC}$.

$\overrightarrow{AB} - \overrightarrow{BC} = \overrightarrow{AC}$.

$\overrightarrow{BA} - \overrightarrow{BC} = \overrightarrow{AC}$

$M \left(0; \dfrac{5}{2} \right)$.

$M \left(0; \dfrac{10}{3} \right)$.

$M \left(\dfrac{5}{2}; 0 \right)$.

$M(0;3)$

A. $S=20\sqrt{7}$

B. $S=10\sqrt{3}$

C. $S=5\sqrt{3}$

D. $S=10\sqrt{7}$

A. $\overrightarrow{BA}+\overrightarrow{BD}=\overrightarrow{BC}$

B. $\overrightarrow{BA}+\overrightarrow{BC}=\overrightarrow{BD}$

C. $\overrightarrow{BA}+\overrightarrow{BC}=2\overrightarrow{OB}$

D. $\overrightarrow{BA}+\overrightarrow{BC}=2\overrightarrow{DO}$

A. $S=\dfrac{1}{2} a.b.\sin C$

B. $S=a.b.\sin A$

C. $S=\dfrac{1}{2} a.b.\sin B$

D. $S=\dfrac{1}{2} a.b.\sin A$

A. $\vec{u}=(5;2)$

B. $\vec{u}=(-5;2)$

C. $\vec{u}=(2;5)$

D. $\vec{u}=(2;-5)$