Đề thi Học kì 2 Toán 12 năm 2025-2026 trường THPT Núi Thành (Đà Nẵng)

$d(A,(\alpha))=\dfrac{\left|ax_0+by_0+cz_0+d\right|}{\sqrt{a^2+b^2+c^2}}$

$d(A,(\alpha))=\dfrac{\left|ax_0+by_0+cz_0+d\right|}{\sqrt{x_0^2+y_0^2+z_0^2}}$

$d(A,(\alpha))=\dfrac{\left|ax_0+by_0+cz_0+d\right|}{a^2+b^2+c^2}$

$d(A,(\alpha))=\dfrac{\left|ax_0+by_0+cz_0+d\right|}{\sqrt{a+b+c}}$

$\displaystyle \int\left[2+f(x)\right]dx = \int 2dx + \int f(x)dx$ .

$\displaystyle \int 2f(x) dx = \int 2dx.\int f(x) dx$ .

$\displaystyle \int\left[f(x)+g(x)\right]dx = \int f(x) dx + \int g(x) dx$ .

$\displaystyle \int \left[f(x)-g(x)\right] dx = \int f(x) dx - \int g(x) dx$ .

$N(1;-2;3)$ .

$M(-2;-1;1)$ .

$P(2;1;-1)$ .

$Q(2;1;1)$ .

$\dfrac{\left|aa'-bb'+cc'\right|}{\sqrt{a^2+b^2+c^2} \cdot \sqrt{a'^2+b'^2+c'^2}}$ .

$\dfrac{\left|aa'+bb'+cc'\right|}{\sqrt{a^2+b^2+c^2} \cdot \sqrt{a'^2+b'^2+c'^2}}$ .

$\dfrac{\left|aa'-bb'+cc'\right|}{\sqrt{a^2+b^2+c^2} + \sqrt{a'^2+b'^2+c'^2}}$ .

$\dfrac{\left|aa'+bb'+cc'\right|}{\sqrt{a^2+b^2+c^2} + \sqrt{a'^2+b'^2+c'^2}}$ .

$V=\pi \int \limits_a^b f(x^2) dx$ .

$V=\pi \int \limits_a^b f^2(x) dx$ .

$V=\pi \int \limits_a^b \left|f(x)\right| dx$ .

$V=\pi^2 \int \limits_a^b f(x) dx$ .

$(P_3): x - y - 2z + 1 = 0$

$(P_2): x - 3y + 4z - 2 = 0$

$(P_1): 2x - 6y + 4z - 2 = 0$

$(P_4): -2x + 6y - 4z - 1 = 0$

$\begin{cases} x = 2 + t \\ y = 1 - 2t \\ z = -3 + 3t \end{cases}$

$\begin{cases} x = 2 + t \\ y = 1 + 2t \\ z = -3 - 3t \end{cases}$

$\begin{cases} x = 2 + t \\ y = 1 - 2t \\ z = -3 - 3t \end{cases}$

$\begin{cases} x = 1 + 2t \\ y = -2 + t \\ z = 3 - 3t \end{cases}$