Trắc nghiệm Lũy thừa với số mũ tự nhiên của một số hữu tỉ Toán 7

xⁿ

x.n

nˣ

x + n

$x^n=x\cdot x\cdot x\cdot...\cdot x$ (có n thừa số x) $\left(x\inℚ,n\inℕ,n\gt1\right)$

x⁰ = 0 (x ≠ 0)

x¹ = x

1ⁿ = 1 ( $n\inℕ$)

$\dfrac{1}{6}$

$\dfrac{-1}{2}$

$\dfrac{1}{8}$

$\dfrac{-1}{8}$

$\left(x\cdot y\right)^n=x^n\cdot y^n$

$\left(x\cdot y\right)^n=x^n\cdot y$

$\left(\dfrac{x}{y}\right)^n=\dfrac{x^n}{y^n}$ (y ≠ 0)

$\left(\dfrac{x}{y}\right)^n=x^n:y^n$ (y ≠ 0)

$\dfrac{81}{16}$

6

$\dfrac{3}{4}$

$\dfrac{12}{16}$

$x^m:x^n=x^{m-n}$ (x ≠ 0, m ≥ n)

$x^m\cdot x^n=x^{m.n}$

$\left(x^m\right)^n=x^{m+n}$

$\dfrac{x^m}{x^n}=x^{m:n}$ (x ≠ 0, m ≥ n)

$-\dfrac{1}{32}$

$\dfrac{1}{32}$

$-\dfrac{1}{10}$

$\dfrac{1}{10}$

− 49

14

− 14

49

$\left(-\dfrac{3}{2}\right)^{15}$

$\left(-\dfrac{27}{32}\right)^2$

$\left(\dfrac{3}{2}\right)^{15}$

$\left(\dfrac{27}{32}\right)^2$

$x=\dfrac{1}{256}$

$x=\dfrac{1}{16}$

$x=-\dfrac{1}{256}$

$x=-\dfrac{1}{16}$

$x=\dfrac{25}{9}$

$x=\dfrac{3}{5}$

$x=\dfrac{9}{25}$

$x=\dfrac{9}{5}$

0

$\dfrac{25}{16}$

$\dfrac{5}{4}$

Không xác định

− 27

$-\dfrac{1}{9}$

− 13

1