Trắc nghiệm Tập hợp số thực Toán 7

B = $\left(3,4;1,\left(231\right);3\dfrac{5}{7};6,74283\ldots\right)$

B = $\left(1,\left(231\right);3\dfrac{5}{7};6,74283\ldots;-\sqrt{25}\right)$

B = $\left(3\dfrac{5}{7};1,\left(231\right);3,4;-\sqrt{25}\right)$

B = {3,4; 1,(231); 6,74283…; $-\sqrt{25}$ }

C = $\left(3\dfrac{5}{7};-\sqrt{8};\dfrac{4}{3}\right)$

C = {3,22143…; $-\sqrt{8}$ }

C = $\left(3,22143\ldots;1,4\left(21\right);3\dfrac{5}{7}\right)$

C = $\left(1,4\left(21\right)\text{;}3\dfrac{5}{7};\dfrac{4}{3}\right)$

A’ = $\left(7;-2,34521...;3\dfrac{1}{2};5\right)$

A’ = $\left(7;2,34521...;-\dfrac{7}{2};-\sqrt{25}\right)$

A’ = $\left(-7;2,34521...;-\dfrac{7}{2};-\sqrt{25}\right)$

A’ = $\left(-7;-2,34521...;-\dfrac{7}{2};5\right)$

{ 7 }

{ -7 }

{ $\emptyset$ }

{ 7; -7 }

{-25; 25}

{5}

{-5; 5}

{25}

$\left(\dfrac{11}{2};1,5\right)$

$\left(5;\dfrac{3}{2}\right)$

$\left(\dfrac{11}{2};\dfrac{2}{3}\right)$

$\left(\dfrac{11}{2};-1,5\right)$

{ 1; 2; 3; 4 }

{-1; -2; -3; -4 }

{-1; -2; 0; 1; 2 }

{-1; -2; -3; 1; 2; 3 }

B

C’

B’

C

B

C’

A

C

$-2\dfrac{1}{4}$

$\dfrac{9}{4}$

-4,5

$-\dfrac{9}{4}$

$\left(-3\right)\gt\left(\dfrac{3}{2}\right)$

$\left(-3\right)\lt\left(\dfrac{3}{2}\right)$

$\left(-3\right)=\left(\dfrac{3}{2}\right)$

không so sánh được

$\left(-1\dfrac{4}{5}\right)\gt\left(\dfrac{9}{5}\right)$

$\left(-1\dfrac{4}{5}\right)\lt\left(\dfrac{9}{5}\right)$

Không so sánh được

$\left(-1\dfrac{4}{5}\right)=\left(\dfrac{9}{5}\right)$

$\left(\dfrac{4}{3}\right)$

{ -1,(3)}

$\left(-1,\left(3\right);\dfrac{4}{3}\right)$

$\left(-\dfrac{3}{4};\dfrac{3}{4}\right)$

$\dfrac{5}{2}$

$-\dfrac{5}{2}$

$\dfrac{2}{5}$

$-\dfrac{2}{5}$

$\sqrt{5}\lt\sqrt{\left(-7\right)}$

$\sqrt{5}\gt\sqrt{\left(-7\right)}$

Không so sánh được

$\sqrt{5}=\sqrt{\left(-7\right)}$