Đề thi Giữa kì 2 Toán 10 năm 2023-2024 trường THPT Thăng Long (Tp.HCM)

30.

330.

25.

150.

9.

6.

54.

18.

$x^{5}+10x^4 y+40x^3 y^{2}+40x^{2} y^{3}+10x y^{4}+2 y^{5}$.

$x^{5}+10x^4 y+20x^3 y^{2}+20x^{2} y^{3}+10x y^{4}+2 y^{5}$.

$x^{5}+10x^4 y+40x^3 y^{2}+80x^{2} y^{3}+40x y^{4}+32 y^{5}$.

$x^{5}+10x^4 y+40x^3 y^{2}+80x^{2} y^{3}+80x y^{4}+32 y^{5}$.

$\to{AB} = (4; -5)$.

$\to{AB} = (-3; -6)$.

$\to{AB} = (-4; 5)$.

$\to{AB} = (2; 1)$.

$\to{u} = (2; -1)$.

$\to{u} = (-2; 1)$.

$\to{u} = (2; 1)$.

$\to{u} = (-2; -1)$.

$ext{√}2$.

$5\text{√}2$.

10.

5.

$\to{a} + \to{b} = (-4; 6)$.

$\to{a} + \to{b} = (2; -2)$.

$\to{a} + \to{b} = (-3; -8)$.

$\to{a} + \to{b} = (4; -6)$.

$\left\{ \begin{array}{l} x=1+3t \\ y=-2+4t \end{array}\right.$

$\left\{ \begin{array}{l} x=3+t \\ y=4-2t \end{array}\right.$

$\left\{ \begin{array}{l} x=3+4t \\ y=1-2t \end{array}\right.$

$\left\{ \begin{array}{l} x=-3+t \\ y=-4-2t \end{array}\right.$