Đề thi Giữa kì 2 Toán 12 năm 2024-2025 trường THPT Lê Lợi (Kon Tum)

$\int \sin x \, dx = \cos x + C$.

$\int \sin x \, dx = -\cos x + C$.

$\int \sin x \, dx = -\sin x + C$.

$\int \sin x \, dx = \sin x + C$.

$V = \pi^2 \int_1^2 \sqrt{x}dx$.

$V = \pi \int_1^2 \sqrt{x}dx$.

$V = \pi^2 \int_1^2 x dx$.

$V = \pi \int_1^2 x dx$.

$\int f(x) dx = x + \sin x + C$.

$\int f(x) dx = \cos x + C$.

$\int f(x) dx = x + \cos x + C$.

$\int f(x) dx = x - \cos x + C$.

5.

0.

1.

-1.

$f(x)=6x^2 - 2 + C$.

$f(x) = \frac{1}{2} x^4 - x^2 + x + C$.

$f(x) = 6x^2 - 2$.

$f(x) = \frac{1}{2} x^4 - x^2 + x$.

$M_2(1;2;4).$

$M_3 (2;1;4).$

$M_4 (2;4;-1).$

$M_1 (4;2;1).$

$3x - 2y + 4z - 4 = 0$.

$3x - 2y + 4z + 4 = 0$.

$3x + 2y + 4z + 8 = 0$.

$3x - 2y + 4z + 5 = 0$.

$\displaystyle \int_{a}^{b}kf(x)\,dx = \int_{a}^{b}f(x)\,dx.$

$\displaystyle \int_{a}^{b}[f(x)\cdot g(x)]\,dx=\int_{a}^{b}f(x)\,dx \cdot \int_{a}^{b}g(x)\,dx.$

$\displaystyle \iint[f(x)+g(x)]\,dx = \int_{a}^{b}f(x)\,dx + \int_{a}^{b}g(x)\,dx.$

$\displaystyle \iint[f(x)-g(x)]\,dx = \int_{a}^{b}f(x)\,dx + \int_{a}^{b}g(x)\,dx.$

$\dfrac{2025^{x+1}}{2025} + C.$

$2025^x + C.$

$2025^x.\ln 2025 + C.$

$\dfrac{2025^x}{\ln 2025} + C.$

$\left| \int_a^b [f(x) - g(x)] dx \right|$

$\int_a^b |f(x) - g(x)| dx.$

$\iint_a^b [f(x) - g(x)] dx.$

$\int_a^b |f(x) + g(x)| dx.$

$I=5.$

$I=2.$

$I=4.$

$I=6.$